Range to zero a .243 at?

I have seen an article which advises zeroing 243 at 25yds. This would give max of 3” plus/minus of centre out to 300. Has anyone tried this close zero?
 
i did read this article too.it stated
"If you sight in your .243 for 100 yards, its MBPR will drop to 200 yards. Because at that distance the point of impact is -3.3" --but thats fine i felt as most shots are 100 yards im thinking and having a 3 " holdover at 200 seems fine by me if i shot that far out--and i would not,not just now anyways other than on target gongs and ive already found that on 5" gongs an aim point on its top seems to hit just fine at 200 with a .243 and 95grain remmys
 
I agree with JCS, an inch high at 100y.
If possible check this at 50 and 150y if possible.
Jackson Rifle website has a free ballistic calculator too.
Input your known data, chronograph would help but not necessary
Pretty straight forward.
 
The metric equivalent of 1” at 100 yards is 4cm at 100m.

Conveniently the distance from base to the start of the shoulder of a .243 or 308 case is a little of 39mm. So you have a useful measuring tool with you.

This gives you a zero at 200m give or take a few metres. And to 250m bullet will impact +/- 5cm either side of point of aim. Ie pretty much either side of the cross hair in most 4A reticle stalking scopes.
 
Problem with MPBR type thinking is, that by definition you miss more than half of your shots at max range (assuming that shot dispersion is random).

Instead you should think how accurately YOU can shoot in field conditions. Let's say you want +- one inch trajectory. So what is the distance you can shoot 2 inch consistent groups, that don't wander around, in FIELD CONDITIONS? Or better expressed, stay within one inch of POA.

When you have that distance, check the trajectory with calculator (with exact info). If rifle was zeroed for that distance, does the bullet stay +- one inch along the trajectory? If yes, you've found your zero distance and it's also your MPBR. If not, move zero distance closer until the trajectory requirement is fulfilled.

(of course you should take the shot dispersion into count along the whole trajectory, but it's quite easy to figure out by playing with calculator)
 
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